Outputting QVariant::User to qDebug() comes out as a random type

For example:

QApplication app(argc, argv);

QVariant d = QVariant::fromValue<QJSValue>(QJSValue());

qDebug() << d.type() << d;

Can output:

QVariant::QWidget* QVariant(QJSValue, )

QVariant::type() does not carry full type information, it only contains QVariant::User. This is passed as is to QMetaType::typeName() which does not seem correct. Instead it could perhaps print User or Unknown.