Weird behaviour when connecting signals using lambda in a loop

import sys
from PySide6.QtWidgets import (QLineEdit, QPushButton, QApplication,QRadioButton, QVBoxLayout, QDialog,QMainWindow, QLabel)

class Form(QDialog):
    def set_label(self,t,x):
        if t:
            self.lab.setText(x)
            print(x)
    def __init__(self, parent=None):
        super(Form, self).__init__(parent)
        self.lab = QLabel("ok")
        self.r1 = QRadioButton("1")
        self.r2 = QRadioButton("2")
        layout = QVBoxLayout()
        layout.addWidget(self.lab)
        layout.addWidget(self.r1)
        layout.addWidget(self.r2)
        self.setLayout(layout)
        self.set_label(True,'okok')
        ### This would work
        #self.r1.toggled.connect(lambda t: self.set_label(t,"1"))
        #self.r2.toggled.connect(lambda t: self.set_label(t,"2"))
        for num in [1,2]:
            if num == 1:
                x = self.r1
            else:
                x = self.r2
            print(num)
            print(x)
            x.toggled.connect(lambda toggled: self.set_label(toggled, f"{num}"))
            # This would work
            #x.toggled.connect(lambda toggled,num=num: self.set_label(toggled, f"{num}"))

if __name__ == '__main__':
    app = QApplication(sys.argv)
    form = Form()
    form.show()
    sys.exit(app.exec_())

F = lambda: None
def set_f(f):
    global F
    F = f
def p(a,b):
    print(a,b)
for x in range(1,4):
    j =  lambda t: p(t,x)
    set_f(j)
    F(2)