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  1. Qt for Python
  2. PYSIDE-325

Creating a QWidget without a QApplication causes Python interpreter to quit.

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    • Icon: Bug Bug
    • Resolution: Duplicate
    • Icon: P3: Somewhat important P3: Somewhat important
    • 6.0
    • 1.2.x
    • PySide
    • Windows 7 64bit,
      Python: Python 2.7.11 (v2.7.11:6d1b6a68f775, Dec 5 2015, 20:32:19) [MSC v.1500 32 bit (Intel)] on win32
      >>> PySide.__version__
      '1.2.4'

      I hope I am reporting this right, anyway. When in the Python Interpreter. If you attempt to create a QWidget before a QApplication, you get the following error. AND the interpreter quits. I would have expected an exception to be raised and the interpreter to stay open. It is only a minor annoyance, and really one should only get bit once by this.

      e.g.
      C:\Temp>python
      Python 2.7.11 (v2.7.11:6d1b6a68f775, Dec 5 2015, 20:32:19) [MSC v.1500 32 bit (Intel)] on win32
      Type "help", "copyright", "credits" or "license" for more information.
      >>> from PySide import QtGui, QtCore
      >>> myWidget = QtGui.QWidget()
      QWidget: Must construct a QApplication before a QPaintDevice

      C:\Temp>

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            ctismer Christian Tismer
            busfault Thomas Middleton
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              Created:
              Updated:
              Resolved:

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