Details
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Suggestion
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Resolution: Unresolved
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P2: Important
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QDS 4.5
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None
Description
Trying to create a "no-code" approach to creating a StackLayout demo. I have a quick control button inside of Page01. I cannot access the onClicked signal from the button.
In this example I have a stackedLayout with two "page" components inside of it. Each page has two controls, a button to go forward and back and a control that will change something like color.
Page01 should also include all of the signals from the two controls inside of it correct?
An issue here is that "Signal" is not available as a property type. The only way to create a signal is to go into the code editor and write it.