QPushButton: button in pressed state if shown in other button's pressed state

Notice that the second button is in a pressed state after the first is pressed and released.

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#include <QtGui>

class EventButton : public QPushButton
{
public:
inline EventButton(const QString &text, QWidget *p) : QPushButton(text, p)
{
}

virtual void mousePressEvent(QMouseEvent *ev)

{ qDebug() << Q_FUNC_INFO << text(); QPushButton::mousePressEvent(ev); }

virtual void mouseReleaseEvent(QMouseEvent *ev)

{ qDebug() << Q_FUNC_INFO << text(); QPushButton::mouseReleaseEvent(ev); }

};

class MyWidget : public QWidget
{
Q_OBJECT
public:
MyWidget(QWidget *parent = 0) : QWidget(parent)

{ button1 = new EventButton("Press 1", this); button2 = new EventButton("Press 2", this); connect(button1, SIGNAL(pressed()), this, SLOT(recreate()), Qt::QueuedConnection); button2->hide(); }

public slots:
void recreate()

{ button1->hide(); // handel the input of the first widget (here button1) button2->show(); // for the next input }

private:
QPushButton *button1;
QPushButton *button2;
};

#include "main.moc"

int main(int argc, char **argv)
{
QApplication a(argc, argv);
MyWidget w;
w.show();
return a.exec();
}