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  1. Qt
  2. QTBUG-48109

WinRT: There might be an exception when starting a Qt quick application

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    • Icon: Bug Bug
    • Resolution: Done
    • Icon: P1: Critical P1: Critical
    • 5.6.0 RC
    • 5.6.0 Alpha
    • Core: Other
    • None
    • Windows 8.1 Enterprise x64
      MSVC 2013
      Nokia Lumia 820 (WinPhone 8.1)
      Nokia Lumia 620 (WinPhone 8.1)
    • WinRT
    • ceec35a6deb0e14cb2edadab8dbd18cfeff7320f

      When I start a quick application (for examples qtquickcontrols/examples/quick/dialogs/systemdialogs) sometimes an exception is thrown on startup:

      Unhandled exception at 0x68BB7787 (Qt5Guid.dll) in systemdialogs.exe: 0xC0000005: Access violation reading location 0x00000000

      Call Stack:

      >       Qt5Guid.dll!QWindowSystemInterface::handleApplicationStateChanged(Qt::ApplicationState newState, bool forcePropagate) Line 133  C++
       qwinrtd.dll!QWinRTScreen::onVisibilityChanged(ABI::Windows::UI::Core::ICoreWindow * __formal, ABI::Windows::UI::Core::IVisibilityChangedEventArgs * args) Line 1095     C++
qwinrtd.dll!`Microsoft::WRL::Callback<ABI::Windows::Foundation::ITypedEventHandler<ABI::Windows::UI::Core::CoreWindow *,ABI::Windows::UI::Core::VisibilityChangedEventArgs *>,QWinRTScreen,ABI::Windows::UI::Core::ICoreWindow *,ABI::Windows::UI::Core::IVisibilityChangedEventArgs *>'::`2'::ComObject::Invoke(ABI::Windows::UI::Core::ICoreWindow * arg1, ABI::Windows::UI::Core::IVisibilityChangedEventArgs * arg2) Line 498       C++
        [External Code]

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            samuelnevala Samuel Nevala
            owolff Oliver Wolff
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              Created:
              Updated:
              Resolved:

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