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  1. Qt
  2. QTBUG-90404

Function.prototype.call() on undefined results in error

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    Description

          QJSEngine engine;
          QJSValue result = engine.evaluate(QStringLiteral("Array.prototype.map.call(undefined, function (a) {return a; } );"));
          qDebug() << result.toString(); 

      Results in 

      "TypeError: Value is undefined and could not be converted to an object" 

      I believe that this is not correct. The expected behavior is that an undefined this parameter is converted to the global object unless strict mode is enabled.

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              qt.team.quick.subscriptions Qt Quick and Widgets Team
              rweickelt Richard Weickelt
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                Updated:
                Resolved:

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