Inconsistent display of byte arrays

The following snippet:

#include <stdint.h>

int main()
{
	const char          ascii0[] = "Hello";
	const uint8_t       ascii1[] = "Hello";
	const unsigned char ascii2[] = "Hello";
	const char          data0[] = "\x12\x34\x00\x56\x78";
	const uint8_t       data1[] = "\x12\x34\x00\x56\x78";
	const unsigned char data2[] = "\x12\x34\x00\x56\x78";
	return ascii0[0]
			+ ascii1[0]
			+ ascii2[0]
			+ data0[0]
			+ data1[0]
			+ data2[0];
}

generates total different Debugger outputs for the various arrays.

• ascii0 and ascii2 are shown completely including the NULL terminator. It is possible to view the array elementsas char, dec and hex when expanding the view
• ascii1 is similar, but does not show the NULL terminator. When exanding, you only see the decimal value.
• data0 shows no summary, but you can expand it to see all values Edit: that was due to the "Raw Data" value display format. If you change it back, it behaves like unsigned char.
• data1 is truncated at the first NULL which is really painful when debugging binary data in uint8_t arrays
• data2 is nearly perfect. Only improvement would be a display format that shows the summary in hex

Summary:

• Don't truncate unit8_t[] at the NULL and handle it like char[]
• Show a summary for char[] when it contains binary data (like unsigned char)
• Add a display format to show all characters in hex, as this is mandatory for binary data. Up to now the array is always interpreted as a string in some encoding.