References to members of template arguments doesn't work when creator has seen a class by the same name in a different namepace

Consider the following code

struct A {
    void foo();

    struct B {
        int b;
    };
};

template<typename T>
struct Smart
{
    T* get() { return 0; }
};

namespace foo {
    struct B {
    };
}

using namespace foo;

void A::foo()
{
    Smart<B> sb1;
    sb1.get()->b;

    Smart<A::B> sb2;
    sb2.get()->b;
}

Creator thinks that that "sb1.get()" returns an instance of the foo::B class but it in fact returns an instance of A::B, you can see this by placing the cursor on the lower case b, it doesn't reference anything. This works fine in a regular compiler like Clang or GCC.

The "sb2.get()->b" statement works just fine.